n^2+2n+29=4

Solution for n^2+2n+29=4 equation:

Simplifying
n2 + 2n + 29 = 4

Reorder the terms:
29 + 2n + n2 = 4

Solving
29 + 2n + n2 = 4

Solving for variable 'n'.

Reorder the terms:
29 + -4 + 2n + n2 = 4 + -4

Combine like terms: 29 + -4 = 25
25 + 2n + n2 = 4 + -4

Combine like terms: 4 + -4 = 0
25 + 2n + n2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-25' to each side of the equation.
25 + 2n + -25 + n2 = 0 + -25

Reorder the terms:
25 + -25 + 2n + n2 = 0 + -25

Combine like terms: 25 + -25 = 0
0 + 2n + n2 = 0 + -25
2n + n2 = 0 + -25

Combine like terms: 0 + -25 = -25
2n + n2 = -25

The n term is 2n.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2n + 1 + n2 = -25 + 1

Reorder the terms:
1 + 2n + n2 = -25 + 1

Combine like terms: -25 + 1 = -24
1 + 2n + n2 = -24

Factor a perfect square on the left side:
(n + 1)(n + 1) = -24

Can't calculate square root of the right side.

The solution to this equation could not be determined.